3(2cos^2(x)-1)=5cos(x)+1

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Solution for 3(2cos^2(x)-1)=5cos(x)+1 equation: 


Simplifying
3(2cos2(x) + -1) = 5cos(x) + 1

Multiply cos2 * x
3(2cos2x + -1) = 5cos(x) + 1

Reorder the terms:
3(-1 + 2cos2x) = 5cos(x) + 1
(-1 * 3 + 2cos2x * 3) = 5cos(x) + 1
(-3 + 6cos2x) = 5cos(x) + 1

Multiply cos * x
-3 + 6cos2x = 5cosx + 1

Reorder the terms:
-3 + 6cos2x = 1 + 5cosx

Solving
-3 + 6cos2x = 1 + 5cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5cosx' to each side of the equation.
-3 + -5cosx + 6cos2x = 1 + 5cosx + -5cosx

Combine like terms: 5cosx + -5cosx = 0
-3 + -5cosx + 6cos2x = 1 + 0
-3 + -5cosx + 6cos2x = 1

Add '3' to each side of the equation.
-3 + -5cosx + 3 + 6cos2x = 1 + 3

Reorder the terms:
-3 + 3 + -5cosx + 6cos2x = 1 + 3

Combine like terms: -3 + 3 = 0
0 + -5cosx + 6cos2x = 1 + 3
-5cosx + 6cos2x = 1 + 3

Combine like terms: 1 + 3 = 4
-5cosx + 6cos2x = 4

Reorder the terms:
-4 + -5cosx + 6cos2x = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + -5cosx + 6cos2x = 0

The solution to this equation could not be determined.

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